Title 03. MOTION IN A STRAIGHT LINE.pdf ✅

PAPER 1 (1.) A car starts from rest and moves with constant acceleration. The ratio of distance covered in nth second to that covered in n seconds is : (1) 2 2 1 n n − (2) 2 2 1 n n + (3) 2 2 1 n n − (4) 2 2 1 n n + (2.) Which of the following statements is true for a car moving on the road : (1) With respect to the frame of reference attached to the ground, the car is at rest (2) With respect to the frame of reference attached to the person sitting in the car, the car is at rest (3) With respect to the frame of reference attached to the person outside the car, the car is at rest (4) None of these (3.) A body is projected vertically in upward direction from ground with speed 20 m / s. It will come on ground after ( ) 2 g =10 m / s : (1) 2sec (2) 4sec (3) 20sec (4) 12sec (4.) The x t − graph representing an object at rest is : (1) (2) (3) (4) (5.) If a body starts from rest, the time in which it covers a particular displacement with uniform acceleration is : (1) inversely proportional to the square root of the displacement (2) inversely proportional to the displacement (3) directly proportional to the displacement (4) directly proportional to the square root of the displacement (6.) The coordinates of object with respect to a frame of reference at t = 0 are (−1,0,3). If t = 5 s , its coordinates are (−1,0, 4) , then the obj ect is in : (1) motion along Z-axis (2) motion along X -axis
JOIN US NEET TEST PAPERS TO GET FULL PAPERS INCLUDE SCORE BOOSTER, RANK BOOSTER QUESTIONS PURELY NCERT BASED, INCLUDES PAGE NUMBER CHAPTER WISE CLICK HERE OR
(3) motion along Y-axis (4) rest position between t = 0 s and t = 5 s (7.) The position-time graph for a uniform motion is represented as : (1) (2) (3) (4) (8.) A ball projected vertically upwards direction with initial velocity 55 m / s . The distance travelled in th 6 second of motion will be ( ) 2 g =10 m / s (1) 2.5 m (2) 1.25 m (3) Zero (4) 6 m (9.) A body thrown vertically upwards direction it passes from same height at 4sec and 6sec respectively. Then find total height reached by body ( ) 2 g =10 m / s (1) 150 m (2) 125 m (3) 200 m (4) 250 m (10.) A car starts from rest at time t = 0 s from the origin O and picks up speed till t =10 s and thereafter moves with uniform speed till t =16 s . The brakes are applied and the car stops at t = 20 s and x = 296 m . The position-time graph which best represents the above situation is : (1) (2)
(3) (4) None of these (11.) A ball is released from the top of a tower of height h metres. It takes T seconds to reach the ground. What is the position of the ball in T /3 seconds : (1) 9 h metres from the ground (2) 7 h / 9 metres from the ground (3) 8 h / 9 metres from the ground (4) 17 h /18 metres from the ground (12.) If the velocity of a particle is 2 v At Bt = + , where A and B are constants, then the distance travelled by it between t =1 s to t 2 s = : (1) 3 4 2 A B + (2) 3 7 A B + (3) 3 7 A B 2 3 + (4) 2 3 A B + (13.) The displacement of a particle is given by ( ) 2 x t t = − ( 2) , where x is in metres and t in seconds. The distance covered by the particle in first 4 s is (1) 8 m (2) 4 m (3) 12 m (4) 16 m (14.) A ship A is moving westwards with a speed of 1 20 km h− and a ship B100 km . South of A, is moving northwards with a speed of 1 20 km h− . The time after which the distance between them becomes shortest, is : (1) 2.5 h (2) 5 h (3) 5 2 h (4) 10 2 h (15.) A car travelling at a speed of 30 km / h is brought to a halt in a distance of 8 m by applying brakes. If the same car is moving at a speed of 60 km / hr then it can be brought to a halt with same brakes in: (1) 64 m (2) 32 m (3) 16 m (4) 4 m (16.) A particle experiences constant acceleration for 20 seconds after starting from rest. if it travels a distance 1 S in the first 10 seconds and a distance 2 S in next 10 seconds, then: (1) S S 2 1 = (2) S 2 S 2 1 = (3) S 3 S 2 1 = (4) S 4 S 2 1 = (17.) In figure, displacement-time ( x t − ) graph given below : the average velocity between time t = 5 s and t s = 7 is :