Title RM43 - Module Exercises - Part 1.pdf ✅

GEOTECHNICAL ENGINEERING 3 BLACKWATCH ENGR. PAUL L. LADESMA CE | ME 1 | PPE SITUATION: A river is 10 m deep having a clay layer at the bottom with water content of 40% and specific gravity of 2.70. At a depth of 15 m from the bottom of the river: Determine the total stress, kPa. A. 178.42 B. 187.24 C. 356.25 D. 365.52 SOLUTION: Solve for void ratio: Gsw = eS 2.70 (0.40) = e(1.0); ∴ e = 1.08 Solve for saturated unit weight: γsat = (Gs + e)γw 1 + e γsat = (2.70 + 1.08)(9.81) 1 + 1.08 = 17.828 kN/m3 Solve for Total Stress: PT = Σ γh PT = 10m (9.81) + 15m(17.828) = 365.52 kPa PT = 365. 52 Pa
GEOTECHNICAL ENGINEERING 3 BLACKWATCH ENGR. PAUL L. LADESMA CE | ME 1 | PPE SITUATION: A river is 10 m deep having a clay layer at the bottom with water content of 40% and specific gravity of 2.70. At a depth of 15 m from the bottom of the river: Determine the pore-water pressure, kPa. A. 147.15 B. 245.25 C. 98.10 D. 91.80 SOLUTION: Solve for pore-water pressure: PW = γW h PW = (9.81)(10 m + 15m) = 245.25 kPa PW = 245. 25 kPa

GEOTECHNICAL ENGINEERING 3 BLACKWATCH ENGR. PAUL L. LADESMA CE | ME 1 | PPE SITUATION: A clay layer 5m thick rests beneath a deposit of submerged sand 8m thick. The top of the sand is located 3m below the surface of water. The saturated unit weight of the sand is 25 kN/m3, and the clay is 20 kN/m3. Find the total vertical pressure at mid-height of the clay layer in kPa. A. 329.43 B. 300.00 C. 250.00 D. 279.43 SOLUTION: Total Pressure: PT = Σγh PT = 3γw + 8γsat. sand + 2.5γsat. clay PT = 3(9.81) + 8(25) + 2.5(20) = 279.43 kPa PT = 279. 43 kPa