Title RCD Beams Post-test Solutions.pdf ✅

KIPPAP EDUCATION Post - Test # 3 9. If the beam is reinforced with 2500 sq. mm of bars at the tension side. Determine the depth of the neutra I axis. a. 124.55 mm b. 185.25 mm c. 146.52 mm d. 217.94 mm 10. Determine the nominal moment capacity of the beam. a. 480 kN-m b. 183 kN-m c. 240 kN-m d. 432 kN-m 11. For normal weight of concrete, the modulus of elasticity of concrete (Ee) may be taken as: a. 4,700-vfc MPa b. 3,700-vfc MPa C. 2,700-v'fc MPa d. 5,700-vfc psi 12. Concrete covers shall be provided for reinforced concrete for protection of reinforcement bars from rusting. For non-prestressed concrete cast- in-place slabs and walls in contact with the ground having less than or equal to 36 mm diameter rebar, what is the minimum specified concrete cover? a. 40 mm b. 20 mm c. 25 mm d. 30 mm 13. It is a system of slab construction in which there are no beams or other projections below the bottom surface of the slab. a. Ribbed Slab b. Flat Slab c. One way Slab d. Flat Plates 14. If the structure is subjected to a load for a long period of time, it will continue to deform until a sudden fracture occurs. a. Creep b. Fatigue c. Toughness d. Yield Stress 15. The material has the same composition at every point but the elasticity may not be the same in all directions. a. Ductile b. Homogenous c. Heterogenous d. Aeolotropic Situation 4: A doubly reinforced concrete beam has an effective depth of 600 mm and a width of 325 mm. It is reinforced with a compressive bars at the top of are 1490 mm2 and 4970 mm2 tension bars at the bottom. Given: fc' = 28 MPa; fy = 414 MPa Cover to centroid of compression reinforcement = 65 mm 16. Determine the depth of the compression block in mm. a. b. 125.36 mm 147.48 mm c. 186.26 mm d. 219.13 mm 17. Determine the ultimate moment capacity in kN- m. a. 326 b. 222 C. 945 d. 954 Situation 5: A circular column is reinforced by 10-25 mm diameter bars with a clear cover of 40 mm for 10 mm diameter spiral. Given: Diameter, D = 500 mm (I)= 0.75 Nu = 540 kN fc' = 28 MPa and fy = 275 MPa 18. Calculate the nominal shear stress on concrete if the 10 mm diameter spirals are spaced 70 mm in centers if Vu = 360 kN. a. 0.93 MPa b. 0.68 MPa c. 1.12 MPa d. 1.17 MPa 19. Calculate the nominal shear capacity of the column using simplified calculations. a. 462 kN b. 338 kN c. 215 kN d. 516 kN 20. Calculate the required spacing of the 10 mm diameter spirals for a factored shear force Vu= 400 kN. a. 40 mm b. 50 mm c. 60 mm d. 30 mm Prepared by: ENGR. KJHG, 2023

6)Mn=217.3 + ((6) %)Pmax='(E) Mu:265.5 kN -m Mn=1 = 8:295kN-m mar10.5i Assume SRB, TSY! 2952104) = 0.85 (35)a(300)(540 -2) Pmax = 0.725Psal 9 = 65.138 c = A = 68 = 81.4229 a)As:2500 mm2 , T = C;Assume +4! +s = 600(23):3379.223100mi4/on! 2500(415) = 0.85(28)9(350) 9 : 124.55 2 = 4 = 146.52 7 = 2 As (420) = 0.85 (35) (65-138)(300) +s = 600 (EC) As:1384. 19 mm" fs:1549.74.7fy &> 1000 #of 25-mmbars:the TSY! . =144.52 mm = 2.8198 = W3 bars 10)Nominal Capacity SITUATION B b = 350mm fc = 28 NPa Mr: Asfy (d-q) d = 525mm fy:415 MPa 7) Pbal=? :, = 0.85 Mn= 2500 (415) (525 -2) Poal-i.(fy) Mn=480.077 kN - M Pbal = 0.85(28) (0.85) #5(45] Abal = 0.0288 -> STORE